Re: variable in loop

[Les Mikesell <lesmikesell@xxxxxxxxx>]

On 1/2/11 4:27 PM, S Mathias wrote:
> $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done)
> 65 hello.
> $
>
>
> Why doesn't it print:
> 65 hello.................................................................
>
>
>
> What am i missing?
>

Order of operations.  Brace expansion happens before variable substitution 
(echo $i to see the actual value you are getting).

-- 
   Les Mikesell
    lesmikesell@xxxxxxxxx
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