On Thursday, December 02, 2010 07:57 AM, Les Mikesell wrote: > On 12/1/2010 5:44 PM, Ross Walker wrote: >> On Dec 1, 2010, at 5:07 PM, Christopher Chan<christopher.chan@xxxxxxxxxxxxxxx> wrote: >> >>> On Thursday, December 02, 2010 05:09 AM, ann kok wrote: >>>> Hi all >>>> >>>> Anyone can help to let me know how to >>>> >>>> ls -1 | lsattr >>> >>> lsattr `ls -1` >>> >>>> >>>> >>>> ls -al /folder | awk '{ print $2}' | lsattr >>>> >>> >>> >>> for i in `ls -al /folder | awk '{ print $8}'`; do lsattr /folder/$i; done >> >> You can probably do that last one as a pipe to xargs instead of a shell loop. > > I'm missing something here. Why does lsattr need help from ls? > It does not. I don't know why the OP is even trying to do it this way. Just thought I'd demonstrate some bash stuff. :-p _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos