From: Tom Bishop <bishoptf@xxxxxxxxx> >So I have been playing with a RAID 10 f2 ( 2 disks far layout) setup...thanks >for all of the advice..Now I am playing with the format and want to make sure I >have it setup the best that I can, my raid was built using the raid 10 option >with 2 disks with the layout=far, chunk size 512....now I read all of the docs I > >could find about format and stride and stripe size and this is what i came up >with... >mkfs -t ext4 -E stride=128,stripe-width=32 /dev/md0 >Someone let meknow if this looks right, but since i only have two disks to get >my stride 512/4k=128 and then to get my stripe 2/2*128/4=32 >From the mke4fs man page: "stripe-width ... This is typically stride-size * N, where N is the number of data-bearing disks in the RAID" So, I think it is 128 * 1 = 128 Also, have a look at: http://busybox.net/~aldot/mkfs_stride.html JD _______________________________________________ CentOS mailing list CentOS@xxxxxxxxxx http://lists.centos.org/mailman/listinfo/centos