On Sat, Oct 7, 2023 at 11:57 PM Tejun Heo <tj@xxxxxxxxxx> wrote:
>
> On Sat, Oct 07, 2023 at 02:02:59PM +0000, Yafang Shao wrote:
> > +
> > +/**
> > + * bpf_task_cgroup_id_within_hierarchy - Retrieves the associated cgroup ID of a
> > + * task within a specific cgroup1 hierarchy.
> > + * @task: The target task
> > + * @hierarchy_id: The ID of a cgroup1 hierarchy
> > + */
> > +__bpf_kfunc u64 bpf_task_cgroup1_id_within_hierarchy(struct task_struct *task, int hierarchy_id)
> > +{
> > + return task_cgroup1_id_within_hierarchy(task, hierarchy_id);
> > +}
> > +
> > +/**
> > + * bpf_task_ancestor_cgroup_id_within_hierarchy - Retrieves the associated
> > + * ancestor cgroup ID of a task within a specific cgroup1 hierarchy.
> > + * @task: The target task
> > + * @hierarchy_id: The ID of a cgroup1 hierarchy
> > + * @ancestor_level: The cgroup level of the ancestor in the cgroup1 hierarchy
> > + */
> > +__bpf_kfunc u64 bpf_task_ancestor_cgroup1_id_within_hierarchy(struct task_struct *task,
> > + int hierarchy_id, int ancestor_level)
> > +{
> > + return task_ancestor_cgroup1_id_within_hierarchy(task, hierarchy_id, ancestor_level);
> > +}
>
> The same here. Please make one helper that returns a kptr and then let the
> user call bpf_cgroup_ancestor() if desired.
Sure, will do it.
--
Regards
Yafang
