Re: [PATCH] bpf, docs: Fix modulo zero, division by zero, overflow, and underflow

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On 01/05, dthaler1968@xxxxxxxxxxxxxx wrote:
From: Dave Thaler <dthaler@xxxxxxxxxxxxx>

Fix modulo zero, division by zero, overflow, and underflow.
Also clarify how a negative immediate value is used in unsigned division

Signed-off-by: Dave Thaler <dthaler@xxxxxxxxxxxxx>

Acked-by: Stanislav Fomichev <sdf@xxxxxxxxxx>

With a small note below.

---
  Documentation/bpf/instruction-set.rst | 15 +++++++++++++--
  1 file changed, 13 insertions(+), 2 deletions(-)

diff --git a/Documentation/bpf/instruction-set.rst b/Documentation/bpf/instruction-set.rst
index e672d5ec6cc..2ba7c618f33 100644
--- a/Documentation/bpf/instruction-set.rst
+++ b/Documentation/bpf/instruction-set.rst
@@ -99,19 +99,26 @@ code      value  description
  BPF_ADD   0x00   dst += src
  BPF_SUB   0x10   dst -= src
  BPF_MUL   0x20   dst \*= src
-BPF_DIV   0x30   dst /= src
+BPF_DIV   0x30   dst = (src != 0) ? (dst / src) : 0
  BPF_OR    0x40   dst \|= src
  BPF_AND   0x50   dst &= src
  BPF_LSH   0x60   dst <<= src
  BPF_RSH   0x70   dst >>= src
  BPF_NEG   0x80   dst = ~src
-BPF_MOD   0x90   dst %= src
+BPF_MOD   0x90   dst = (src != 0) ? (dst % src) : dst
  BPF_XOR   0xa0   dst ^= src
  BPF_MOV   0xb0   dst = src
  BPF_ARSH  0xc0   sign extending shift right
BPF_END 0xd0 byte swap operations (see `Byte swap instructions`_ below) ======== ===== ==========================================================

+Underflow and overflow are allowed during arithmetic operations,
+meaning the 64-bit or 32-bit value will wrap.  If
+eBPF program execution would result in division by zero,
+the destination register is instead set to zero.
+If execution would result in modulo by zero,
+the destination register is instead left unchanged.
+
  ``BPF_ADD | BPF_X | BPF_ALU`` means::

    dst_reg = (u32) dst_reg + (u32) src_reg;
@@ -128,6 +135,10 @@ BPF_END 0xd0 byte swap operations (see `Byte swap instructions`_ below)

    dst_reg = dst_reg ^ imm32


[..]

+Also note that the division and modulo operations are unsigned,
+where 'imm' is first sign extended to 64 bits and then converted
+to an unsigned 64-bit value.  There are no instructions for
+signed division or modulo.

Less sure about this part, but it looks to be true at least by looking at
the interpreter which does:

DST = DST / IMM

where:

DST === (u64) regs[insn->dst_reg]
IMM === (s32) insn->imm

(and s32 is sign-expanded to u64 according to C rules)

  Byte swap instructions
  ~~~~~~~~~~~~~~~~~~~~~~
--
2.33.4




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