Re: [PATCH bpf-next v4 06/10] bpf: Track provenance for pointers formed from referenced PTR_TO_BTF_ID

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On Sun, Dec 19, 2021 at 07:58:39AM IST, Alexei Starovoitov wrote:
> On Fri, Dec 17, 2021 at 07:20:27AM +0530, Kumar Kartikeya Dwivedi wrote:
> > diff --git a/include/linux/bpf_verifier.h b/include/linux/bpf_verifier.h
> > index b80fe5bf2a02..a6ef11db6823 100644
> > --- a/include/linux/bpf_verifier.h
> > +++ b/include/linux/bpf_verifier.h
> > @@ -128,6 +128,16 @@ struct bpf_reg_state {
> >  	 * allowed and has the same effect as bpf_sk_release(sk).
> >  	 */
> >  	u32 ref_obj_id;
> > +	/* This is set for pointers which are derived from referenced
> > +	 * pointer (e.g. PTR_TO_BTF_ID pointer walking), so that the
> > +	 * pointers obtained by walking referenced PTR_TO_BTF_ID
> > +	 * are appropriately invalidated when the lifetime of their
> > +	 * parent object ends.
> > +	 *
> > +	 * Only one of ref_obj_id and parent_ref_obj_id can be set,
> > +	 * never both at once.
> > +	 */
> > +	u32 parent_ref_obj_id;
>
> How would it handle parent of parent?

When you do:

r1 = acquire();

it gets ref_obj_id as N, then when you load r1->next, it does mark_btf_ld_reg
with reg->ref_obj_id ?: reg->parent_ref_obj_id, the latter is zero so it copies
ref, but into parent_ref_obj_id.

r2 = r1->next;

>From here on, parent_ref_obj_id is propagated into all further mark_btf_ld_reg,
so if we do since ref_obj_id will be zero from previous mark_btf_ld_reg:

r3 = r2->next; // it will copy parent_ref_obj_id

I think it even works fine when you reach it indirectly, like foo->bar->foo,
if first foo is referenced.

... but maybe I missed some detail, do you see a problem in this approach?

> Did you consider map_uid approach ?
> Similar uid can be added for PTR_TO_BTF_ID.
> Then every such pointer will be unique. Each deref will get its own uid.

I'll look into it, I didn't consider it before. My idea was to invalidate
pointers obtained from a referenced ptr_to_btf_id so I copied the same
ref_obj_id into parent_ref_obj_id, so that it can be matched during release. How
would that work in the btf_uid approach if they are unique? Do we copy the same
ref_obj_id into btf_uid? Then it's not very different except being btf_id ptr
specific state, right?

Or we can copy ref_obj_id and also set uid to disallow it from being released,
but still allow invalidation.

> I think the advantage of parent_ref_obj_id approach is that the program
> can acquire a pointer through one kernel type, do some deref, and then
> release it through a deref of other type. I'm not sure how practical is that
> and it feels a bit dangerous.

I think I don't allow releasing when ref_obj_id is 0 (which would be the case
when parent_ref_obj_id is set), only indirectly invalidating them.

--
Kartikeya



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