When we run out of maximum rqnodes, the original queued spin lock slow path falls back to a try lock. In such a case, we are again susceptible to stalls in case the lock owner fails to make progress. We use the timeout as a fallback to break out of this loop and return to the caller. This is a fallback for an extreme edge case, when on the same CPU we run out of all 4 qnodes. When could this happen? We are in slow path in task context, we get interrupted by an IRQ, which while in the slow path gets interrupted by an NMI, whcih in the slow path gets another nested NMI, which enters the slow path. All of the interruptions happen after node->count++. Reviewed-by: Barret Rhoden <brho@xxxxxxxxxx> Signed-off-by: Kumar Kartikeya Dwivedi <memxor@xxxxxxxxx> --- kernel/locking/rqspinlock.c | 8 +++++++- 1 file changed, 7 insertions(+), 1 deletion(-) diff --git a/kernel/locking/rqspinlock.c b/kernel/locking/rqspinlock.c index fdc20157d0c9..df7adec59cec 100644 --- a/kernel/locking/rqspinlock.c +++ b/kernel/locking/rqspinlock.c @@ -255,8 +255,14 @@ int __lockfunc resilient_queued_spin_lock_slowpath(rqspinlock_t *lock, u32 val, */ if (unlikely(idx >= _Q_MAX_NODES)) { lockevent_inc(lock_no_node); - while (!queued_spin_trylock(lock)) + RES_RESET_TIMEOUT(ts); + while (!queued_spin_trylock(lock)) { + if (RES_CHECK_TIMEOUT(ts, ret)) { + lockevent_inc(rqspinlock_lock_timeout); + break; + } cpu_relax(); + } goto release; } -- 2.43.5