Re: [PATCH bpf-next] selftests/bpf: Workaround iters/iter_arr_with_actual_elem_count failure when -mcpu=cpuv4

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On Mon, Jul 8, 2024 at 7:04 PM Alexei Starovoitov
<alexei.starovoitov@xxxxxxxxx> wrote:
>
> On Mon, Jul 8, 2024 at 3:12 PM Andrii Nakryiko
> <andrii.nakryiko@xxxxxxxxx> wrote:
> >
> > On Mon, Jul 8, 2024 at 3:11 PM Andrii Nakryiko
> > <andrii.nakryiko@xxxxxxxxx> wrote:
> > >
> > > On Mon, Jul 8, 2024 at 2:31 PM Eduard Zingerman <eddyz87@xxxxxxxxx> wrote:
> > > >
> > > > On Mon, 2024-07-08 at 13:18 -0700, Alexei Starovoitov wrote:
> > > >
> > > > [...]
> > > >
> > > > > > the 32bit_sign_ext will indicate the register r1 is from 32bit sign extension, so once w1 range is refined, the upper 32bit can be recalculated.
> > > > > >
> > > > > > Can we avoid 32bit_sign_exit in the above? Let us say we have
> > > > > >    r1 = ...;  R1_w=scalar(smin=0xffffffff80000000,smax=0x7fffffff), R6_w=scalar(smin=smin32=0,smax=umax=smax32=umax32=32,var_off=(0x0; 0x3f))
> > > > > >    if w1 < w6 goto pc+4
> > > > > > where r1 achieves is trange through other means than 32bit sign extension e.g.
> > > > > >    call bpf_get_prandom_u32;
> > > > > >    r1 = r0;
> > > > > >    r1 <<= 32;
> > > > > >    call bpf_get_prandom_u32;
> > > > > >    r1 |= r0;  /* r1 is 64bit random number */
> > > > > >    r2 = 0xffffffff80000000 ll;
> > > > > >    if r1 s< r2 goto end;
> > > > > >    if r1 s> 0x7fffFFFF goto end; /* after this r1 range (smin=0xffffffff80000000,smax=0x7fffffff) */
> > > > > >    if w1 < w6 goto end;
> > > > > >    ...  <=== w1 range [0,31]
> > > > > >         <=== but if we have upper bit as 0xffffffff........, then the range will be
> > > > > >         <=== [0xffffffff0000001f, 0xffffffff00000000] and this range is not possible compared to original r1 range.
> > > > >
> > > > > Just rephrasing for myself...
> > > > > Because smin=0xffffffff80000000 if upper 32-bit == 0xffffFFFF
> > > > > then lower 32-bit has to be negative.
> > > > > and because we're doing unsigned compare w1 < w6
> > > > > and w6 is less than 80000000
> > > > > we can conclude that upper bits are zero.
> > > > > right?
> > > >
> > > > Sorry, could you please explain this a bit more.
> > >
> > > Yep, also curious.
> > >
> > > But meanwhile, I'm intending to update bpf_for() to something like
> > > below to avoid this code generation pattern:
> > >
> >
> > Well, thank you, Gmail, for messed up formatting. See [0] for properly
> > formatted diff.
> >
> >   [0] https://gist.github.com/anakryiko/08a4374259469803af4ea2185296b0cb
>
> Not that simple. It needs sizeof(start)==8 extra hack like bpf_cmp().

I'm forgetting the details, but I feel like sizeof() == 4 was
important for bpf_cmp() to compare wX registers instead of always
comparing Rx. But in this case I think we are fine with always working
with full 64-bit Rx registers. Or is there some correctness issue
involved?

> And the same with 'end'. So it will get just as ugly.
> Let's make the verifier smarter instead.

Oh, absolutely, let's. But that doesn't solve the problem of someone
using bpf_for() with the latest Clang on an older kernel that doesn't
yet have this smartness, does it? Which is why I want to mitigate that
on the bpf_for() side in addition to improvements on the verifier
side.





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