On Tue, 9 Jul 2024 12:11:33 +0200
Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
> On Mon, Jul 08, 2024 at 04:11:27PM -0700, Andrii Nakryiko wrote:
> > +#ifdef CONFIG_UPROBES
> > +/*
> > + * Heuristic-based check if uprobe is installed at the function entry.
> > + *
> > + * Under assumption of user code being compiled with frame pointers,
> > + * `push %rbp/%ebp` is a good indicator that we indeed are.
> > + *
> > + * Similarly, `endbr64` (assuming 64-bit mode) is also a common pattern.
> > + * If we get this wrong, captured stack trace might have one extra bogus
> > + * entry, but the rest of stack trace will still be meaningful.
> > + */
> > +static bool is_uprobe_at_func_entry(struct pt_regs *regs)
> > +{
> > + struct arch_uprobe *auprobe;
> > +
> > + if (!current->utask)
> > + return false;
> > +
> > + auprobe = current->utask->auprobe;
> > + if (!auprobe)
> > + return false;
> > +
> > + /* push %rbp/%ebp */
> > + if (auprobe->insn[0] == 0x55)
> > + return true;
> > +
> > + /* endbr64 (64-bit only) */
> > + if (user_64bit_mode(regs) && *(u32 *)auprobe->insn == 0xfa1e0ff3)
> > + return true;
>
> I meant to reply to Josh suggesting this, but... how can this be? If you
> scribble the ENDBR with an INT3 things will #CP and we'll never get to
> the #BP.
Hmm, kprobes checks the instruction and reject if it is ENDBR.
Shouldn't uprobe also skip the ENDBR too?
Thank you,
>
> Also, we tried very hard to not have a literal encode ENDBR (I really
> should teach objtool about this one :/). If it somehow makes sense to
> keep this clause, please use: gen_endbr()
--
Masami Hiramatsu (Google) <mhiramat@xxxxxxxxxx>
