Re: [PATCH bpf-next] bpf, docs: Clarify PC use in instruction-set.rst

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On Fri, Apr 26, 2024 at 10:11 AM Dave Thaler <dthaler1968@xxxxxxxxxxxxxx> wrote:
>
> This patch elaborates on the use of PC by expanding the PC acronym,
> explaining the units, and the relative position to which the offset
> applies.
>
> Signed-off-by: Dave Thaler <dthaler1968@xxxxxxxxxxxxxx>
> ---
>  Documentation/bpf/standardization/instruction-set.rst | 5 +++++
>  1 file changed, 5 insertions(+)
>
> diff --git a/Documentation/bpf/standardization/instruction-set.rst b/Documentation/bpf/standardization/instruction-set.rst
> index b44bdacd0..5592620cf 100644
> --- a/Documentation/bpf/standardization/instruction-set.rst
> +++ b/Documentation/bpf/standardization/instruction-set.rst
> @@ -469,6 +469,11 @@ JSLT      0xc    any      PC += offset if dst < src          signed
>  JSLE      0xd    any      PC += offset if dst <= src         signed
>  ========  =====  =======  =================================  ===================================================
>
> +where 'PC' denotes the program counter, and the offset to increment by
> +is in units of 64-bit instructions relative to the instruction following
> +the jump instruction.  Thus 'PC += 1' results in the next instruction
> +to execute being two 64-bit instructions later.

The last part is confusing.
"two 64-bit instructions later"
I'm struggling to understand that.
Maybe say that 'PC += 1' skips execution of the next insn?





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