On 2023/9/28 17:59, Björn Töpel wrote:
Pu Lehui <pulehui@xxxxxxxxxxxxxxx> writes:
From: Pu Lehui <pulehui@xxxxxxxxxx>
In the current RV64 JIT, if we just don't initialize the TCC in subprog,
the TCC can be propagated from the parent process to the subprocess, but
the TCC of the parent process cannot be restored when the subprocess
exits. Since the RV64 TCC is initialized before saving the callee saved
registers into the stack, we cannot use the callee saved register to
pass the TCC, otherwise the original value of the callee saved register
will be destroyed. So we implemented mixing bpf2bpf and tailcalls
similar to x86_64, i.e. using a non-callee saved register to transfer
the TCC between functions, and saving that register to the stack to
protect the TCC value. At the same time, we also consider the scenario
of mixing trampoline.
Hi!
The RISC-V JIT tries to minimize the stack usage, e.g. it doesn't have a
fixed pro/epilogue like some of the other JITs. I think we can do better
here, so that the pass-TCC-via-register can be used, and the additional
stack access can be avoided.
Today, the TCC is passed via a register (a6) and can be viewed as a
"state" variable/transparent argument/return value. As you point out, we
loose this when we do a call. On (any) calls we move the TCC to a
callee-saved register.
WDYT about the following scheme:
1 Pickup the arm64 bpf2bpf/tailmix mechanism of just clearing the TCC
for the main program.
2 For BPF helper calls, move TCC to s6, perform the call, and restore
a6. Dito for kfunc calls (BPF_PSEUDO_KFUNC_CALL).
3 For all other calls, a6 is passed transparently.
For 2 bpf_jit_get_func_addr() can be used to determine if the callee is
a BPF helper or not.
In summary; Determine in the JIT if we're leaving BPF-land, and need to
move the TCC to a callee-saved reg, or not, and save us a bunch of stack
store/loads.
Valuable scheme. But we need to consider TCC back propagation. Let me
show an example of calling subprog with TCC stored in A6:
prog1(TCC==1){
subprog1(TCC==1)
-> tailcall1(TCC==0)
-> subprog2(TCC==0)
subprog3(TCC==0) <--- should be TCC==1
-\-> tailcall2 <--- can't be called
}
We call prog1 and TCC is 1. prog1 has two subprogs, subprog1 and
subprog3. subprog1 calls tailcall1 and TCC become to 0. tailcall1 call
subprog2 and then return to prog1 with TCC is 0. At this time, subprog3
cannot call tailcall2 because TCC is 0. But TCC should be 1 here.
The question is A6 cannot be saved and restored, that is why I saved A6
in stack at prologue, and restored at epilogue.
Björn
