All, The i686 archroot on the x86_64 box worked perfectly building i686 TDE. However, as I tweak packages, I need to 'uninstall' a package from the rw-layer without cleaning the entire archroot. Since this is i686 on a x86_64 box how do I properly chroot the archroot so that I can run pacman -R package name? Can I somehow: mount --bind some_dev $CHROOT/dev mount -t proc none $CHROOT/proc mount -t sysfs none $CHROOT/sys cd $CHROOT some_chroot_cmd So that the i686 system will be functional enough to remove a package? I have seen the Arch64_FAQ page discussing the linux32 wrapper working with i686 chroots created by installing with i686 ISO "quickinstall", but this setup is just an i686 archroot. (will it work?) I want to avoid cleaning the archroot or deleting and recreating a new one just to test minor changes to package content adjustments due the setup requiring several hundred dependencies and packages to rebuild. What say the experts? -- David C. Rankin, J.D.,P.E.