Re: [users@httpd] Apache 2.0.53 will not display png from 4 line python script

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* Simon Hook wrote:

> I have a 4 line python script which should display a png that is in the
> same directory as the script. The script is:
>
> #!d:/apps/Python23/python.exe
>
> fp = open('tmp.png','rb')
> print "Content-type: image/png\n"
> print fp.read()
> fp.close()
>
> Any ideas would be much appreciated.

(1) Missing an empty line between the headers and the body
(2) Never use print with binary data
(3) Use binary mode on stdout on Win32 systems when working with binary data

#!d:/apps/Python23/python.exe

import os, sys, msvcrt

fp = open('tmp.png', 'rb')
print "Content-type: image/png\n\n"
msvcrt.setmode(sys.stdout.fileno(), os.O_BINARY)
sys.stdout.write(fp.read())
fp.close()

(untested)

nd
-- 
"Solides und umfangreiches Buch"
                                          -- aus einer Rezension

<http://pub.perlig.de/books.html#apache2>

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