We are receiving URLS that we need to do two things to: 1) First unescape the entire URL including the query string 2) Change the question mark in front of the text STRING to its escaped version - %3F Then take the transformed URL and perform a GET back to the Apache server that did the two transformations. The enclosed Perl program does what I described above. However, we do not have mod_perl installed on these Apache servers so I have to use a mod_rewrite solution. ---- snip ----- use strict; use File::Slurp; use URI::Escape; my $url = File::Slurp::read_file STDIN ; # unescape the entire URL with query string. this is very important # as the %2F characters must be sent to recipient with them unescaped $url = uri_unescape $url; # escape the question mark just before "STRING" $url =~ s!([?]STRING)!uri_escape($1)!e; print $url --------------------------------------------------------------------- The official User-To-User support forum of the Apache HTTP Server Project. See <URL:http://httpd.apache.org/userslist.html> for more info. To unsubscribe, e-mail: users-unsubscribe@xxxxxxxxxxxxxxxx " from the digest: users-digest-unsubscribe@xxxxxxxxxxxxxxxx For additional commands, e-mail: users-help@xxxxxxxxxxxxxxxx
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