On Mon, Jan 1, 2018 at 8:37 AM, Simon Walter <simon@xxxxxxxxxx> wrote:
> I am interested in how apr_bucket_split(e, point) works.
>
> It seems that after splitting e, it still contains everything after
> point. Only when flattened is this data "removed" from e.
>
> If that is correct, then is it also correct to assume that I would need
> to use apr_bucket_read with snprintf and make a copy of the data in
> order to display it accurately?
>
> Is there another way to show the contents of buckets after they've been
> split/manipulated?
>
> I need to flatten the brigade (or flush it to a socket? that's a
> different question), but for debugging purposes, to check my logic, I am
> trying to see the contents of individual buckets.
>
I don't think that's right. For example mod_substitute does this to
remove the pattern that matched from the input:
#define SEDRMPATBCKT(b, offset, tmp_b, patlen) do { \
apr_bucket_split(b, offset); \
tmp_b = APR_BUCKET_NEXT(b); \
apr_bucket_split(tmp_b, patlen); \
b = APR_BUCKET_NEXT(tmp_b); \
apr_bucket_delete(tmp_b); \
} while (0)
The dump_brigade macro in .gdbinit in the source tree will help here.
You can also use the code there to add your own trace.
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