I'm not a mod_lua expert, esp as it relates to exposing the full Apache httpd API... it is possible that using r.handler and specifying the proxy may work. > On Dec 18, 2015, at 8:05 AM, Jose Thomas <jostho@xxxxxxxxx> wrote: > > Jim, > > Sorry, I could not find the documentation on how to do this using mod_lua. Can you please point me there ? > > In my current setup which is on httpd 2.2 - we use modpython. For routing requests (based on a header) we use a simple python script. For refiring the request (when a custom response code is received), another python script is configured in a "PythonOutputFilter". That script internally uses the python requests library. > > We are upgrading to httpd 2.4 and wanted to see if this code can be ported to mod_lua. I have already ported the first script (routing) to lua. Where i am clueless, is how to resend the request to backend for the 2nd script in a "LuaOutputFilter". > > Thanks & regards, > Jose > > On Fri, Dec 18, 2015 at 5:08 PM, Jim Jagielski <jim@xxxxxxxxxxx> wrote: > In general, if you prepend the URL w/ 'proxy:' and then > use it in a subrequest, it will be processed as a proxy > request. > > On Dec 17, 2015, at 9:21 AM, Jose Thomas <jostho@xxxxxxxxx> wrote: > > > > All, > > > > I am using httpd 2.4 with mod_proxy (http) routing requests to multiple backends. > > > > I have a strange requirement. If a backend responds with a custom response code - i need to re-execute the request to a different backend. > > > > What would be the right way to implement this functionality ? > > > > I was looking at mod_lua for a solution. The idea is to use a "LuaOutputFilter" to check the response code, and then re-execute the request with a different backend. How can i refire the request ? Should i use a lua httpclient library for this ? Is there a easier way to do this ? > > > > Any other suggestions/comments are welcome. > > > > Version of stack > > * Apache 2.4.6 > > * Lua 5.1.4 > > > > Regards, > > Jose > > ____________ > > > > > > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: users-unsubscribe@xxxxxxxxxxxxxxxx > For additional commands, e-mail: users-help@xxxxxxxxxxxxxxxx > > --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscribe@xxxxxxxxxxxxxxxx For additional commands, e-mail: users-help@xxxxxxxxxxxxxxxx
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