Christian
Check "drm_sched_start" which is invoked from gpu_recover() , there is a "drm_sched_start_timeout()" in the tail
/Monk
-----Original Message-----
From: Christian König <ckoenig.leichtzumerken@xxxxxxxxx>
Sent: Thursday, May 9, 2019 3:18 PM
To: Liu, Monk <Monk.Liu@xxxxxxx>; amd-gfx@xxxxxxxxxxxxxxxxxxxxx
Subject: Re: [PATCH] drm/sched: fix the duplicated TMO message for one IB
[CAUTION: External Email]
Am 09.05.19 um 06:31 schrieb Monk Liu:
> we don't need duplicated IB's timeout error message reported
> endlessly, just one report per timedout IB is enough
Well, NAK. We don't need multiple timeout reports, but we really need to restart the timeout counter after handling it.
Otherwise we will never run into a timeout again after handling one and it isn't unlikely that multiple IBs in a row doesn't work correctly.
Christian.
>
> Signed-off-by: Monk Liu <Monk.Liu@xxxxxxx>
> ---
> drivers/gpu/drm/scheduler/sched_main.c | 5 -----
> 1 file changed, 5 deletions(-)
>
> diff --git a/drivers/gpu/drm/scheduler/sched_main.c
> b/drivers/gpu/drm/scheduler/sched_main.c
> index c1aaf85..d6c17f1 100644
> --- a/drivers/gpu/drm/scheduler/sched_main.c
> +++ b/drivers/gpu/drm/scheduler/sched_main.c
> @@ -308,7 +308,6 @@ static void drm_sched_job_timedout(struct work_struct *work)
> {
> struct drm_gpu_scheduler *sched;
> struct drm_sched_job *job;
> - unsigned long flags;
>
> sched = container_of(work, struct drm_gpu_scheduler, work_tdr.work);
> job = list_first_entry_or_null(&sched->ring_mirror_list,
> @@ -316,10 +315,6 @@ static void drm_sched_job_timedout(struct
> work_struct *work)
>
> if (job)
> job->sched->ops->timedout_job(job);
> -
> - spin_lock_irqsave(&sched->job_list_lock, flags);
> - drm_sched_start_timeout(sched);
> - spin_unlock_irqrestore(&sched->job_list_lock, flags);
> }
>
> /**
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