In the show_member_offset() function, when trying to handle function
pointers, the case for "(*" is handled. However, if the function
pointer returns a pointer or a pointer to a pointer, then the
condition is unhandled. This results in the offset not being printed.
Fix by first checking if the member is potentially a function pointer,
then checking if it returns a pointer or a pointer to a pointer.
Signed-off-by: John Pittman <jpittman@xxxxxxxxxx>
---
symbols.c | 11 +++++++++--
1 file changed, 9 insertions(+), 2 deletions(-)
diff --git a/symbols.c b/symbols.c
index a2d5c6c..5d7da6e 100644
--- a/symbols.c
+++ b/symbols.c
@@ -8356,8 +8356,15 @@ show_member_offset(FILE *ofp, struct datatype_member *dm, char *inbuf)
}
} else if (c) {
for (i = 0; i < c; i++) {
- if (STRNEQ(arglist[i], "(*")) {
- target = arglist[i]+2;
+ if (strstr(inbuf, "(*")) {
+ if (STRNEQ(arglist[i], "(*"))
+ target = arglist[i]+2;
+ else if (STRNEQ(arglist[i], "*(*"))
+ target = arglist[i]+3;
+ else if (STRNEQ(arglist[i], "**(*"))
+ target = arglist[i]+4;
+ else
+ continue;
if (!(t1 = strstr(target, ")")))
continue;
*t1 = NULLCHAR;
--
2.17.2
--
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