On Mon, Nov 24, 2014 at 3:02 PM, Vasiliy Tolstov <v.tolstov@xxxxxxxxx> wrote:
> Hi. I'm try to shape disk via total_iops_sec in libvirt
> libvirt 1.2.10
> qemu 2.0.0
>
> Firstly when i'm run vm with predefined
> <total_iops_sec>5000</total_iops_sec> i have around 11000 iops (dd
> if=/dev/sda bs=512K of=/dev/null)
> After that i'm try to set via virsh --total_iops_sec 10 to want to
> minimize io, but nothing changed.
> After that i'm reboot vm with <total_iops_sec>10</total_iops_sec> and
> get very slow io, but this expected. But libvirt says that i have is
> around 600 iops.
>
> My questions is - why i can't change total_iops_sec in run-time, and
> why entered values does not equal values getting from libvirt ?
>
> Thanks for any suggestions and any help.
>
> --
> Vasiliy Tolstov,
> e-mail: v.tolstov@xxxxxxxxx
> jabber: vase@xxxxxxxxx
>
Hello Vasiliy,
can you please check actual values via qemu-monitor-command domid '{
"execute": "query-block"}', just to be sure to pin the potential
problem to the emulator itself?
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