On Wed, Jun 27, 2007 at 03:39:30PM +0200, Omer Khalid wrote: > Hi, > > I have the following code working on libvirt 0.1.9: > > ######################################## > conn = libvirt.openReadOnly(None) > if conn == None: > print 'Failed to open connection to the hypervisor' > #sys.exit(1) > > try: > domains = conn.listDomainsID() > num = conn.numOfDomains() > except: > print 'Failed to find the list of domains' > > for i in range(num): > try: > dom0 = conn.lookupByID(domains[i]) > domInfo = dom0.info() > except: > print "Unexpected error:", sys.exc_info() > > ############################################## > > For legacy reason, I have to get it working on libvirt 0.1.8 but I am > constantly getting the following error: > > Unexpected error: (<class libvirt.libvirtError at 0xb7f49f2c>, < > libvirt.libvirtError instance at 0xb7f4f2cc>, <traceback object at > 0xb7f44c5c>) Try adding an exception handler that prints out useful information rather than raw python object references for a start... Its impossible to debug this unless you get the text associated with the exception. Regards, Dan. -- |=- Red Hat, Engineering, Emerging Technologies, Boston. +1 978 392 2496 -=| |=- Perl modules: http://search.cpan.org/~danberr/ -=| |=- Projects: http://freshmeat.net/~danielpb/ -=| |=- GnuPG: 7D3B9505 F3C9 553F A1DA 4AC2 5648 23C1 B3DF F742 7D3B 9505 -=|