On Mon, Mar 12, 2007 at 05:16:52PM +0000, Richard W.M. Jones wrote:
> * Fix qemudDebug when debug not enabled
Its not clear what was broken about the existing code ?
This chunk:
> #ifdef ENABLE_DEBUG
> #define qemudDebug(...) qemudLog(QEMUD_DEBUG, __VA_ARGS__)
> #else
> -#define qemudDebug(fmt, ...) do { } while(0);
> +#define qemudDebug(fmt, ...)
> #endif
Will break / silently change code semantics, if qemudDebug is used in
situations like
if (foo)
qemudDebug("blah")
wizz()
Because when compiling without debug, it turns into
if (foo)
wizz()
Regards,
Dan.
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