Hello,
it is not so straightforward if there are more than one minion.
For copyfile, the overlord part uses:
if data:
self.parent.run("copyfile", "append", [remotepath,
xmlrpclib.Binary(data)])
This applies to all target minions because it is the same file for all.
I can't do the opposite for getfile, because the action differs from
one minion to the other (the files can have different lengths)
I need to do something like this because I cut the files in chunks to get them:
for chunknum in range(chunkslen):
checksum,chunk = self.parent.run("getfile", "getchunk",
[chunknum, source]).items()[0][1]
It is fine when I restrict the target to one minion.
Do you know how I could do the run on one single minion (replacing
parent.run), so I just have to loop over the minions ?
I don't.
Louis
2010/9/30 seth vidal <skvidal@xxxxxxxxxxxxxxxxx>:
> On Thu, 2010-09-30 at 20:09 +0200, Louis Coilliot wrote:
>> Ok, but what if we reach the maximum filename length ?
>>
>> Wouldn't it be preferable to put the files in subfolder named with the
>> minion hostname ?
>
>
> sounds fine to me.
>
> -sv
>
>
>
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