On 05/08/2021 11:35, François Patte wrote:
Bonjour,
I have a raid-1 array of 2 disks (1 Tb) and I want to
replace these disks by 2 2Tb disks.
Here is the result of lsblk for these disks:
sde 8:64 0 931,5G 0 disk
├─sde1 8:65 0 40G 0 part
│ └─md4 9:4 0 40G 0 raid1
│ ├─systeme-swap 253:1 0 4G 0 lvm [SWAP]
│ ├─systeme-var 253:2 0 15G 0 lvm /var
│ └─systeme-chiffre 253:3 0 15G 0 lvm
└─sde2 8:66 0 891,5G 0 part
└─md5 9:5 0 891,4G 0 raid1
└─data-home 253:5 0 891G 0 lvm /home
sdf 8:80 0 931,5G 0 disk
├─sdf1 8:81 0 40G 0 part
│ └─md4 9:4 0 40G 0 raid1
│ ├─systeme-swap 253:1 0 4G 0 lvm [SWAP]
│ ├─systeme-var 253:2 0 15G 0 lvm /var
│ └─systeme-chiffre 253:3 0 15G 0 lvm
└─sdf2 8:82 0 891,5G 0 part
└─md5 9:5 0 891,4G 0 raid1
└─data-home 253:5 0 891G 0 lvm /home
My idea is to stop the array, remove one disk and have
this array in degraded mode with the other disk. Then plug
a new disk (2Tb) on which I build a new array in degraded
mode with all partitions and lvm needed. Then I transfer
all the data from the remaining 1Tb disk to the new array,
replace the 1Tb disk by a new 2Tb disk and then
synchronize the new array.
Is it the good way to proceed? Or is there another better way?
Thank you for all advices.
I imagine you might have your own reasons. I would, just I
have been doing for long time, leave it all to LVM(which
underneath as far as I know uses "md" for raid, at least it
some cases).
That way you have just one business logic to deal with, to
manage, thus much lower TCO. (lvm2 has, in my opinion,
fantastic man pages)
choose your PVs, create VG(s) and as an example:
$ -> lvcreate --type raid0 -i 4 -I 16 -n 0 -l 90%pv
dellH200.InternalB /dev/sd{c..f}
and so on...
If you can, turn the situation into an opportunity to "migrate".
cheers, L
--
François Patte
UFR de mathématiques et informatique
Laboratoire MAP5 --- UMR CNRS 8145
Université Paris Descartes
45, rue des Saints Pères
F-75270 Paris Cedex 06
Tél. +33 (0)1 4286 2145
http://www.math-info.univ-paris5.fr/~patte
<http://www.math-info.univ-paris5.fr/~patte>
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