When I concatenate 2 or more shell command with pipe (|), I get only the status of last one. For example: "some-cmd | logger -t "some-cmd messages:"; echo $?" If "some-cmd" fail with status !=0 I get always status of last one, in this case 0 In my case if the first command fail, I must send a warning message A more simple example is: "false | true" I want get status 1, of first command (false), not 0 (true) I have also try "sh -e -c 'false || exit 2|true'; echo $?" but I get always 0 How to I get first status and break the chains of pipes ? Many thanks -- Dario Lesca (inviato dal mio Linux Fedora 28 Workstation) |
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