From: Jonathan Ryshpan <jonrysh@xxxxxxxxxxx>
Subject: Re: tail for a list of files
To: users@xxxxxxxxxxxxxxxxxxxxxxx
Message-ID: <1520171408.2173.42.camel@xxxxxxxxxxx>
Content-Type: multipart/alternative; boundary="=-PuQtDYwItgjfcLx2Crff"
--=-PuQtDYwItgjfcLx2Crff
Content-Type: text/plain; charset="UTF-8"
Content-Transfer-Encoding: 7bit
On Sat, 2018-03-03 at 11:15 -0500, bruce wrote:
Trying to figure out how to do a single line cmd (it should be
possible right??) to do a tail -5 for a list of files???
I thought I could combine find with exec/xargs and tail to generate
the list of files/tail data.. But couldn't figure out the syntax..
find /foo -name "*dog.dat ... tail -5 << obviously not correct.
but
what would work?
I think the easy way is
$ find /foo -name "*dog.dat" | xargs tail -n5
or am I missing something?
I created 4 pdf files using 'touch 123.pdf' through '126.pdf'
find . -name "*.pdf" | tail -n 2
does not 'find' the files in canonical order: it outputs 124.pdf and 126.pdf
Neither does .... | xargs tail -n 2
Trying:
tail -n 2 $(find . -name "*.pdf")
gives:
==> ./125.pdf <==
==> ./123.pdf <==
==> ./124.pdf <==
==> ./126.pdf <==
NOT in order and ignores the 'tail -n 2'
tail -n 2 $(find . -name "*.pdf"| sort) gives the files in order, but
ignores the tail count.
HOWEVER this works:
find . -name "*.pdf" | sort | tail -n 2
./125.pdf
./126.pdf
Geoff
_______________________________________________
users mailing list -- users@xxxxxxxxxxxxxxxxxxxxxxx
To unsubscribe send an email to users-leave@xxxxxxxxxxxxxxxxxxxxxxx
