Re: bash/regex question..

[Boris Epstein <borepstein@xxxxxxxxx>]

Good points. I wonder if it wouldn't be best to do it all in awk. Saves CPU cycles and complexity, IMHO.

Cheers,

Boris.

On Tue, Sep 13, 2016 at 12:26 PM, Gordon Messmer <gordon.messmer@xxxxxxxxx> wrote:

On 09/12/2016 04:37 PM, bruce wrote:

awk -F': ' '{print $2}' | tail -1 |  sed 's/.*storeId=\(.*\).&/\1/'

You've got good answers, especially Cameron's.  It had one error, though.  If the URL is in a variable, it needs to be an argument to printf:

 url="" href="http://venturacollege.bncollege.com/webapp/wcs/stores/servlet/BNCBHomePage?storeId=78236&campusId=78236&userId=-1002&catalogId=10001&ddkey=http:BNCBMultiCampusPageCmd" rel="noreferrer" target="_blank">http://venturacollege.bncollege.com/webapp/wcs/stores/servlet/BNCBHomePage?storeId=78236&campusId=78236&userId=-1002&catalogId=10001&ddkey=http:BNCBMultiCampusPageCmd'
 store_id=$( printf '%s\n' | tr '?&' '\012\012' | sed -n 's/^storeId=//p' )

The reason I like Cameron's advice in particular is that it doesn't use ".*".  In this case, performance isn't measurably bad, but using ".*" can eat a lot of CPU cycles.

https://blog.mariusschulz.com/2014/06/03/why-using-in-regular-expressions-is-almost-never-what-you-actually-want

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