Re: bash/regex question..

[Lorenzo Sutton <lorenzofsutton@xxxxxxxxx>]

On 13/09/2016 01:37, bruce wrote:
> Hey.
>
> Simple question.
>
> Got a basic string..
> http://venturacollege.bncollege.com/webapp/wcs/stores/servlet/BNCBHomePage?storeId=78236&campusId=78236&userId=-1002&catalogId=10001&ddkey=http:BNCBMultiCampusPageCmd
>
> trying to get the internal sub-string "78236"

If Python is available you can do:

s = 
'http://venturacollege.bncollege.com/webapp/wcs/stores/servlet/BNCBHomePage?storeId=78236&campusId=78236&userId=-1002&catalogId=10001&ddkey=http:BNCBMultiCampusPageCmd'

print(s.split('storeId=')[1].split('&campus')[0])

To do it directly in Bash, assuming your string is $TRING:

python -c "print('$STRING'.split('storeId=')[1].split('&campusId')[0])"

Lorenzo.

> I can remove the beginning portion, but can't figureout the rest of the
> regex to remove the subsequent chars..
>
> awk -F': ' '{print $2}' | tail -1 |  sed 's/.*storeId=\(.*\).&/\1/'
>
> Any help/pointers/thoughts..
>
> thanks
>
>
>
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