Re: bash/regex question..

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On Mon, Sep 12, 2016 at 7:38 PM bruce <badouglas@xxxxxxxxx> wrote:
I can remove the beginning portion, but can't figureout the rest of the regex to remove the subsequent chars..

awk -F': ' '{print $2}' | tail -1 |  sed 's/.*storeId=\(.*\).&/\1/'

Any help/pointers/thoughts..

thanks



Assuming $x contains the string, you can do this with pure bash:

if [[ $x =~ storeId=([^&]*) ]]; then echo "${BASH_REMATCH[1]}"; fi

or with sed:

echo $x | sed -e 's/.*storeId=\([^&]*\).*/\1/'

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