On Mon, 01 Aug 2016 17:23:43 -0700, stan wrote:
> On Mon, 1 Aug 2016 22:21:58 +0000 (UTC)
> "Amadeus W.M." <amadeus84@xxxxxxxxxxx> wrote:
>
>> On Mon, 01 Aug 2016 09:34:51 -0700, stan wrote:
>>
>> > On Mon, 1 Aug 2016 04:30:03 +0000 (UTC)
>> > "Amadeus W.M." <amadeus84@xxxxxxxxxxx> wrote:
>> > [snip]
>> >> Unfortunately nothing worked.
>> >>
>> >>
>> >> In the cuda distribution there is a host_config.h file which
>> >> contains the following lines:
>> >>
>> >> #if __GNUC__ > 4 || (__GNUC__ == 4 && __GNUC_MINOR__ > 9)
>> >>
>> >> #error -- unsupported GNU version! gcc versions later than 4.9 are
>> >> not supported!
>> >>
>> >> #endif /* __GNUC__ > 4 || (__GNUC__ == 4 && __GNUC_MINOR__ > 9) */
>> >>
>> >>
>> >> This checks the version of the compiler and triggers an error with
>> >> gcc-6.1 even if I pass --std=gnu89 which was the default C standard
>> >> in gcc-4.9.
>> >
>> > You don't have write access to that file? If you do, you could just
>> > comment out that check.
>> >
>> >
>> I do have write access to that file, but I imagine that compiler check
>> is there for a reason, so I would rather use the right compiler than
>> not check for it. Chances are the cuda code won't compile (correctly)
>> if I skip the check. Still, maybe worth a shot.
>
> But that's why you put in the --std=gnu89 flag. You're telling gcc to
> pretend that it is gcc 4.9, even though it's 6.1, so you are manually
> doing the check. That is, even though the compiler is 6.1, it's going
> to emulate 4.9.
That's what I thought too, but try this:
// Compile as
// g++ -o gnuc gnuc.cpp
// then as
// g++ --std=gnu++11 -o gnuc gnuc.cpp
#include <iostream>
#include <cstdlib>
using namespace std;
int main(int argc, char * argv[])
{
cout << __GNUC__ << "." << __GNUC_MINOR__ << endl;
return 0;
}
It always outputs 6.1, whether or not you compile it with the --std flag.
And if you think about it, __GNUC__ is probably a macro defined in the
compiler at compile time, so it can't possibly change at run time. Haven't
checked, but it's a good guess.
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