On 05/04/2016 10:09 AM, Jon LaBadie wrote:
The '*' means "zero or more digits". Don't forget that zero.
The first match is where there are zero digits, i.e. at the
beginning of the line. So sed replaces it with "//" (nothing).
However, usually regexps are greedy so they match as much as possible,
not the minimum. And somehow it does work when you use /g so it is
matching more.
Try sed 's/[0-9]*/X/' to confirm.
You really want sed 's/[0-9][0-9]*//' which reads a digit
followed by zero or more additional digits.
Or use + as has been mentioned elsewhere in this thread.
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