On Mon, 19 Aug 2013, Mark Haney wrote:
I've hit a problem I can't quite figure out which a bash script I'm writing. I'm trying to copy backup files in the format 2013-August-18--1123.zip to an NFS share.
I want to have the script copy the file with just the date. In bash I've setup vars that get the current date:
# Date variables
log_year=`date "+%Y"`
log_month=`date "+%B"`
log_day=`date "+%d"`
# Filename format YYYY_MM_DD--HHMM.zip
filename=$log_year"-"$log_month"-"$log_day"--"/*".zip"
The problem is I don't really care about the stuff after the '--'. I.e. from the CLI I'd just 'ls 2013-August-18--*.zip' to get all the files with that date in the
file name. How can I do that in a bash script?
--
Caesar si viveret, ad remum dareris.
Mark Haney
Software Developer/Consultant
mark.haney@xxxxxxxxx
You mean something like this?
************************
#!/bin/sh
# Date variables
log_year=`date "+%Y"`
log_month=`date "+%B"`
log_day=`date "+%d"`
# Filename format YYYY_MM_DD--HHMM.zip
filename="$log_year-$log_month-$log_day--*.zip"
filelist=`ls $filename`
echo $filelist
***************************
billo
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