Re: Finding the size of directory with multiply hardlinked files

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Patrick O'Callaghan wrote:
> On Thu, 2008-03-13 at 19:48 -0700, Dean S. Messing wrote:
> > I have a sequence of directories that have many multiply
> > (cross)hardlinked files, and I'd like to see what their
> > "true" sizes are.  These dirs are backup directories
> > created with something like:
> > 
> > rsync -a --delete --link-dest=/mnt/bkup/backup_A/ \
> >       /dir_to_back_up /mnt/bkup/backup_B/
> > 
> > By "true" sizes I mean this:
> > 
> > Say backup_A was created first.  If I do `du_true
> > backup_A' I shd. see its size.  Now I delete some files
> > in "/dir_to_back_up" and create some other new files.
> > Now I create "backup_B" with the above rsync command.  I'd
> > like for my mythical `du_true' to compute the
> > incremental change in size from backup_A to backup_B.
> > 
> > This seems like a non-trivial problem but maybe I'm just
> > missing something simple.
> 
> What's wrong with "subtract 'du -s backup_B' from 'du -s backup_A'"?

I don't think this works for what I want.  If backup_A and backup_B
happened to be the same size but each file in each directroy was
linked just once, your solution would give back 0 when, in fact, the
amount of space occupied by the the two directories is their sum.

I think the solution requires simultaneous knowledge of both
directories so that two files, one in backup_A and one in backup_B
that are hardlinked together are counted just once.

> If this isn't what you mean, then you need to explain it better. The
> concept of files being "in" a directory is just a convenient fiction.
> Both backup_A and backup_B are just sets of hard links.

Appologies if I wasn't clear.  The post by Roberto Ragusa in this
thread gives both the solution and a clear idea of what I was looking
for.  Apparantly `du' has the smarts to figure out differential
directory sizes, although it's not clear from the man page.

Dean

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