At 10:19 AM -0300 2/28/07, seba bino wrote:
>On 2/27/07, Frank Cox <theatre@xxxxxxxxxxx> wrote:
>> On Tue, 27 Feb 2007 14:12:43 -0800 (PST)
>> Ravi Malghan <rmalghan@xxxxxxxxx> wrote:
>>
>> > Hi: I have installed Fedora 6 on a laptop with 756MB
>> > RAM. With no application started when the machine
>> > boots up, the top is saying that, 601308K is being
>> > used.
>>
>> Type this:
>>
>> free
>>
>> Look at the second line of output data.
>>
>> For example, this is what I have on this machine right now:
>>
>> $ free
>> total used free shared buffers cached
>> Mem: 2057836 1958356 99480 0 77972 1437864
>> -/+ buffers/cache: 442520 1615316
>> Swap: 2031608 344 2031264
>>
>> I am using 442520k of memory, but 1962316k is actually occupied by my active
>> processes, plus what amounts to a cache of what I have been doing
>>recently just
>> in case I might want to do it again soon.
>>
>> Linux uses all available ram for that sort of a cache unless it is otherwise
>> required for something else whereupon it is immediately released and
>>given to
>> the process that asked for it.
>"1962316k is actually occupied by my active"
>How do you calculate that 1962316k is being occupied by your active processes?
Incorrectly. 442520K is used by his ("active") processes. 1615316K is
not; of that, 77922K is used for buffers, 1437864K is used for cache, and
99480K is not used.
--
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' <http://www.georgeanelson.com/>
