aragonx@xxxxxxxxxx wrote:
I bet awk has it's own user list but before I go and subscribe to another
one, I figured I would ask here first. I have the following awk code that
is trying to set a variable of the shell it is running in. It doesn't
work and I've searched high and low to see how to get it to do so.
The reason I don't just use DOMAIN= 'awk blah blah blah' is I want to set
more than one shell variable for each record. But I have to get this
working first. :(
#!/bin/bash
awk '{FS=":"}{system ("DOMAIN=" $1); }
{system ("DOMAIN="$1)};
{system ("echo \"$DOMAIN\"")};
' /etc/passwd
Any help would be appreciated.
This isn't an awk question, it's a 'how unix works' question. A child
process can't change anything in it's parent's environment. Your awk
program will be a child of the shell running it; the system statements
run yet another shell as a child under awk. All of those processes have
their environment strings in protected memory (inherited shared but
copy-on-write).
The var=`command ..` will work, or you can do all of the work that needs
the setting in the lowest level subprocess that has the right values.
--
Les Mikesell
lesmikesell@xxxxxxxxx
