Les Mikesell wrote:
edwardspl@xxxxxxxxxx wrote:
chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward
You can use the symbolic form literally. I think it's easier to
understand. Let the computer do the binary/octal math.
g+rwx means add the read, write, and execute bits for the group.
But I want to know what no of g+rwx...
The + means it is added to the bits already permitted. Look at them as
groups of 3 bits in binary and take the octal value.
user group other
rwx rwx rwx
You'll start with a home dir having rwx --- --- so that's 111 000 000
binary or 700 octal.
Add the group rwx and you get 111 111 000 or 770 octal
So, g+rwx = 770, right ?
chmod +t ( What number of +t ) /home/edward
That's one more bit to the left, 1 000 000 000 binary, so 1000 octal.
Add that to what you have.
Same here, you can type it that way and it means add the "sticky" bit.
Also want to know...
Altogether, the octal value for the mode ends up at 1770. But, as I
said before the computer does a better job of thinking in octal.
So, +t = 1770, right ?
Edward.
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