Rick Stevens wrote:
On Wed, 2007-01-17 at 08:38 -0800, Akemi Yagi wrote:
On Wed, 17 Jan 2007 13:09:09 -0300, Marcelo Magno T. Sales wrote:
Em Quarta 17 Janeiro 2007 12:48, Akemi Yagi escreveu:
On Wed, 17 Jan 2007 12:34:20 -0300, Marcelo Magno T. Sales wrote:
People,
How do I know if the kernel I'm running is the i586 or i686 version?
How about:
rpm -qf /boot/vmlinuz-`uname -r`
provided you have used rpm to install kernel.
Yes, but unfortunately the architecture is not present in the name of the
kernel packages :(
See:
[marcelo.sales@sf002698 ~]$ rpm -qf /boot/vmlinuz-`uname -r`
kernel-2.6.18-1.2849.fc6
[marcelo.sales@sf002698 ~]$ rpm -q kernel
kernel-2.6.18-1.2798.fc6
kernel-2.6.18-1.2849.fc6
OK, there was one piece of info missing. If you want the architecture
etc to appear by default, add the following line to
/etc/rpm/macros.specspo
%_query_all_fmt %%{name}-%%{version}-%%{release}.%%{arch}
Assuming you installed the kernel via RPM, then you can:
# grep M586=y /boot/config-(booted-kernel-version)
If you get no output, then you've got a 686 kernel installed and
running. From a current machine, let's check the Anaconda-installed
kernel...
[root@prophead ~]# grep M586=y /boot/config-2.6.18-1.2798.fc6
CONFIG_M586=y
[root@prophead ~]#
So it was a 586 kernel (gee, what a surprise!). Now, let's check the
kernel I booted:
[root@prophead ~]# uname -r
2.6.18-1.2869.fc6
[root@prophead ~]# grep M586=y /boot/config-`uname -r`
[root@prophead ~]#
No output from the grep command, so I'm running a 686 kernel. To do it
the other way:
[root@prophead ~]# grep M686=y /boot/config-`uname -r`
CONFIG_M686=y
[root@prophead ~]#
Which just proves that M686 IS defined and it's a 686 kernel. Remember,
it's not only what you have INSTALLED, rather what you've BOOTED that's
important.
----------------------------------------------------------------------
- Rick Stevens, Senior Systems Engineer rstevens@xxxxxxxxxxxxxxx -
- VitalStream, Inc. http://www.vitalstream.com -
- -
- The gene pool could use a little chlorine. -
----------------------------------------------------------------------
Along these same lines ...
I have a new test system intended for an embedded application:
-> cat /proc/cpuinfo
processor : 0
vendor_id : AuthenticAMD
cpu family : 5
model : 10
model name : Geode(TM) Integrated Processor by AMD PCS
stepping : 2
cpu MHz : 498.066
cache size : 128 KB
fdiv_bug : no
hlt_bug : no
f00f_bug : no
coma_bug : no
fpu : yes
fpu_exception : yes
cpuid level : 1
wp : yes
flags : fpu de pse tsc msr cx8 pge cmov clflush mmx mmxext
3dnowext 3dnow up
bogomips : 997.22
This guy refuses to install an i686 kernel with:
-bash-3.1# rpm -ivh --replacefiles --replacepkgs kernel-2*.i686.rpm
Preparing... ###########################################
[100%]
package kernel-2.6.18-1.2869.fc6 is intended for a i686 architecture
Is this CPU really a i586?
Is the 'cpu family 5' the identifier used for this consideration? Or is
that a result of booting the i586 kernel?
