On 10/11/06, Dan Track <dan.track@xxxxxxxxx> wrote:
On 10/11/06, Dave Mitchell <davem@xxxxxxxxx> wrote: > On Wed, Oct 11, 2006 at 09:30:13AM +0100, Dan Track wrote: > > Does anybody know where bc stores its calucation while calculating a > > number. Basically I'm running 36000000^36000000. > > Er, you do realise that result will have about 272 million digits? > > -- > Nothing ventured, nothing lost. > Hi Thanks for the heads up :). I realise its going to be big but it all started from someone challenging me about how quick my workstation could do that calculation. I've only started to see that bc might be eating up my memory, and was wondering if there's a way round this. Thanks Dan
Actually How did you know it would contain that many digits? -- fedora-list mailing list fedora-list@xxxxxxxxxx To unsubscribe: https://www.redhat.com/mailman/listinfo/fedora-list
