Hi thanks for great help Everything works from script point of view Just a quick question How will i just get All uidNumber (userid) ?? which commands will show me all uidNumber ?? thanks On Tue, Aug 14, 2012 at 2:18 PM, Rich Megginson <rmeggins@xxxxxxxxxx> wrote: > On 08/14/2012 06:36 AM, Grzegorz Dwornicki wrote: > > I should look similat to this: > > dn: uid=jsmith,ou=users,l=uk,dc=fosiul,dc=lan > changetype: modrdn > newrrdn: uid=new_uid_value > deleteoldrdn: 1 > > - > changetype: modify > replace: loginshell > loginshell: /bin/nologin > - > modify: userPassword > userPassword: asfasfasfasfasfasfasfdPQ= > > > note - there should be no blank lines above - it appears as though the first > "-" is preceded by a blank line - there should be no blank lines > > Also - userPassword should be in clear text - do not send pre-hashed > passwords to the directory server. > > For more information about ldif - man ldif > > > If you see "::" in userPassword this means that hash/password is ecrypted in > base64 before listing in ldif. This rule apply for other attributes aswell. > Usually it's used when attribute have some non-ascii chars. Usually you > don't need to worry about it because most apps can handle this. > > I wrote it by hand soo there may be some errors. The "-" signs are > important, They mean that operation on this entry are not finished and they > provide something like transactions in databases - I noticed this myself. > All operations on entry must be correct or none will be applied. > > Greg. > > send from htc desire z > > 14-08-2012 13:40, "Fosiul Alam" <fosiul@xxxxxxxxx> napisał(a): >> >> Hi >> the theme of this script is , i need to modify uid , password, loginshell >> >> example >> >> ldapsearch -xZZ -D "cn=Directory Manager" -w 'testtest' -b >> "dc=fosiul,dc=lan" "(cn=Fosiul Alam)" loginshell uid userPassword >> # extended LDIF >> # >> # LDAPv3 >> # base <dc=fosiul,dc=lan> with scope subtree >> # filter: (cn=Fosiul Alam) >> # requesting: loginshell uid userPassword >> # >> >> # falam, users, UK, fosiul.lan >> dn: uid=falam,ou=users,l=UK,dc=fosiul,dc=lan >> loginshell: /bin/bash >> uid: falam >> userPassword:: >> e1NTSEF9MkpYSGI2bSs3OFk5SlcySG1kOVcxdjFVUFVHMVA3eXI0dFQvZ2c9PQ= >> = >> >> # search result >> search: 3 >> result: 0 Success >> >> >> So i need to modify it with >> loginshell: /bin/nologin >> uid: delete_falam >> userPassword:: asfasfasfasfasfasfasfdPQ= >> >> >> my first question is : >> what would be the ldif file format for these changes ?? >> >> Thanks for your help . >> -- >> 389 users mailing list >> 389-users@xxxxxxxxxxxxxxxxxxxxxxx >> https://admin.fedoraproject.org/mailman/listinfo/389-users > > > > -- > 389 users mailing list > 389-users@xxxxxxxxxxxxxxxxxxxxxxx > https://admin.fedoraproject.org/mailman/listinfo/389-users > > > > -- > 389 users mailing list > 389-users@xxxxxxxxxxxxxxxxxxxxxxx > https://admin.fedoraproject.org/mailman/listinfo/389-users -- Regards Fosiul Alam 07877100621 http://www.fosiul.co.uk -- 389 users mailing list 389-users@xxxxxxxxxxxxxxxxxxxxxxx https://admin.fedoraproject.org/mailman/listinfo/389-users
