Hi thanks its works fine. perfectly Thanks for your help On Sun, Aug 5, 2012 at 7:24 PM, Fosiul Alam <fosiul@xxxxxxxxx> wrote: > Hi thanks for the script > > one thing i am still confused is > suppose i want to give password "test123" as default password at time > of user creating > how will i create this password and will put that one in > > userPassword: ??? > > > > On Sun, Aug 5, 2012 at 6:29 PM, Grzegorz Dwornicki <gd1100@xxxxxxxxx> wrote: >> Here it is. I was using it to change password on openldap + samba using >> ldap. Samba has its own password attribute. This script takes password from >> user, encrypt it in crypt + call smbpasswd to set password aswell. >> >> $ cat sambaldapnewpass >> #!/bin/bash >> >> #ask user for password: >> >> BASEDN="dc=org1,dc=county" >> USERDN="dc=domain1" >> BASEDIR=/home/lol87 >> >> #login LDAP format: uid=$LOGIN,$USERDN,$BASEDN >> >> if [ -e $1 ]; >> then >> echo "Login" >> read LOGIN >> else >> LOGIN=$1 >> fi >> >> stty -echo >> >> PASS=s >> PASS2=w >> >> while [ $PASS != $PASS2 ]; >> do >> echo "new password:" >> read PASS >> echo "repeat new password:" >> read PASS2 >> done >> >> stty echo >> >> echo $PASS > $BASEDIR/${LOGIN}.tmp >> chmod 400 $BASEDIR/${LOGIN}.tmp >> >> #generate new password for LDAP: >> >> LDAPPASS=$(slappasswd -n -h '{crypt}' -c '$6$%.27s' -T $BASEDIR/${LOGIN}.tmp >> -n) >> echo $LDAPPASS >> rm $BASEDIR/${LOGIN}.tmp >> >> cat $BASEDIR/passchange.ldif | sed ' s/LDAPLOGIN/'$LOGIN'/ ' | sed ' >> s/BASEDN/'$BASEDN'/ ' | sed ' s/USERDN/'$USERDN'/ ' > >> $BASEDIR/passchange_tmp.ldif >> echo "userPassword: $LDAPPASS" >> $BASEDIR/passchange_tmp.ldif >> ldapmodify -x -D "cn=admin,dc=domain1,dc=org1,dc=county" -w some_password < >> $BASEDIR/passchange_tmp.ldif >> >> #rm $BASEDIR/passchange_tmp.ldif >> >> and now: >> $ cat passchange.ldif >> dn: uid=LDAPLOGIN,USERDN,BASEDN >> changetype: modify >> replace: userPassword >> >> You may need to change: >> >> slappasswd -n -h '{crypt}' -c '$6$%.27s' -T $BASEDIR/${LOGIN}.tmp -n >> >> paremeter of -c option defines salt. In my experience i saw many Linux >> distros having diferent salt. Part "$6$" is required (look in man page of >> crypt function) and "%.27s" means to generate 27chars for salt. More details >> you may found in man page of slappasswd. Option -h tells slappasswd to use >> format provided as parameter in this case crypt. >> >> I did not use it for some time soo please treat this as a template for your >> script. I hope this will help you. >> >> Greg. >> >> >> 2012/8/5 Fosiul Alam <fosiul@xxxxxxxxx> >>> >>> Hi Thanks >>> i cant use GUI as the script should take care everything >>> I think it would sha1 . >>> i will try to find a solution if i cant please post your script here >>> >>> it would be really helpful >>> thanks >>> >>> >>> On Sun, Aug 5, 2012 at 3:49 PM, Grzegorz Dwornicki <gd1100@xxxxxxxxx> >>> wrote: >>> > You can use gui. Just edit user account and type thre new password. >>> > Directory server should encypt it before updating the entry in database. >>> > >>> > If you use slappasswd without any parameters it will ask for password >>> > and >>> > generate sha1 hash for you. To use crypt you need to set format to >>> > crypt, >>> > and set proper salt. >>> > >>> > I shold have on my pc example script using slappasswd i wrote it some >>> > time >>> > ago. I can't post it now bcause at the moment im on the bus. If no one >>> > will >>> > post example of using slappasswd then I will later. Unless you will find >>> > solution first. >>> > >>> > Greg. >>> > >>> > Send from htc desire z >>> > >>> > 05-08-2012 15:34, "Fosiul Alam" <fosiul@xxxxxxxxx> napisał(a): >>> > >>> >> HI >>> >> Thanks for reply >>> >> I am using Directory Server 389 >>> >> >>> >> and I am using a script to create the ldif file >>> >> >>> >> So some how i will have to create userpassword .. >>> >> >>> >> But dont understand .. whats the way to do that >>> >> From GUI interface i can create password easily >>> >> so whats the syntax to create userpassword ?? >>> >> >>> >> Regards >>> >> >>> >> >>> >> On Sun, Aug 5, 2012 at 2:25 PM, Christopher Wood >>> >> <christopher_wood@xxxxxxxxx> wrote: >>> >> > Perhaps use slappasswd? >>> >> > >>> >> > On Sun, Aug 05, 2012 at 01:58:33PM +0100, Fosiul Alam wrote: >>> >> >> Hi >>> >> >> I am generating the ldif by script. >>> >> >> but i cant understand how will i generate the userpassword. >>> >> >> >>> >> >> userPassword: {crypt}x >>> >> >> >>> >> >> how this crypt or hash working >>> >> >> >>> >> >> Please give me some lights on this. >>> >> >> >>> >> >> >>> >> >> Regards >>> >> >> -- >>> >> >> 389 users mailing list >>> >> >> 389-users@xxxxxxxxxxxxxxxxxxxxxxx >>> >> >> https://admin.fedoraproject.org/mailman/listinfo/389-users >>> >> > -- >>> >> > 389 users mailing list >>> >> > 389-users@xxxxxxxxxxxxxxxxxxxxxxx >>> >> > https://admin.fedoraproject.org/mailman/listinfo/389-users >>> >> >>> >> >>> >> >>> >> -- >>> >> Regards >>> >> Fosiul Alam >>> >> 07877100621 >>> >> http://www.fosiul.co.uk >>> >> -- >>> >> 389 users mailing list >>> >> 389-users@xxxxxxxxxxxxxxxxxxxxxxx >>> >> https://admin.fedoraproject.org/mailman/listinfo/389-users >>> > >>> > >>> > -- >>> > 389 users mailing list >>> > 389-users@xxxxxxxxxxxxxxxxxxxxxxx >>> > https://admin.fedoraproject.org/mailman/listinfo/389-users >>> >>> >>> >>> -- >>> Regards >>> Fosiul Alam >>> 07877100621 >>> http://www.fosiul.co.uk >>> -- >>> 389 users mailing list >>> 389-users@xxxxxxxxxxxxxxxxxxxxxxx >>> https://admin.fedoraproject.org/mailman/listinfo/389-users >> >> >> >> -- >> 389 users mailing list >> 389-users@xxxxxxxxxxxxxxxxxxxxxxx >> https://admin.fedoraproject.org/mailman/listinfo/389-users > > > > -- > Regards > Fosiul Alam > 07877100621 > http://www.fosiul.co.uk -- Regards Fosiul Alam 07877100621 http://www.fosiul.co.uk -- 389 users mailing list 389-users@xxxxxxxxxxxxxxxxxxxxxxx https://admin.fedoraproject.org/mailman/listinfo/389-users